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TECHNICAL TOOL

Interactive Psychrometric Chart Calculator

Use this psychrometric calculator to read the air state and compare moisture and energy changes between two conditions.

AIR CONDITIONS

State A

Dry bulb −20 to 60°C; RH 0.1–100%; pressure 60–110 kPa. Below freezing, saturation and dew/frost point use the ice basis. Wet-bulb values use the thermodynamic water/ice convention.

STATE A

Relative humidity
60.00 %
Dew / frost point
16.70 °C
Thermodynamic wet bulb
19.47 °C
Humidity ratio (dry-air basis)
11.895 g/kg
Enthalpy (SI reference datum)
55.45 kJ/kg
Specific volume (dry-air basis)
0.8608 m³/kg
Vapour partial pressure
1.9015 kPa

PLOT

Two coordinates. A complete air state.

Blue: RH curves (outer boundary = 100%). Grey long dashes: constant enthalpy. Green short dashes: constant wet bulb. The A–B line joins the endpoints; it is not a simulated equipment path. Swipe horizontally on a phone.

-20-1001020304050600.05.010.015.020.025.030.010%20%30%40%50%60%70%80%90%100%ADry-bulb temperature (°C)Humidity ratio (g/kg)101.325 kPa

Humidity ratio is water mass per mass of dry air, not water per room volume. IP enthalpy is converted from the SI 0°C dry-air datum; absolute values differ from charts using a 0°F datum. Δh uses the same energy difference.

READ THE CHART

Follow temperature, moisture, then energy.

01

Locate the state

Read dry-bulb temperature on the horizontal axis. Move vertically to the selected RH curve. The right-hand scale gives humidity ratio.

02

Read the dew point

Move left at constant humidity ratio until the 100% boundary. This is the dew or frost point at the selected pressure.

03

Compare A → B

Negative Δw means moisture removal. Multiply −Δw in kg/kg by dry-air mass flow for kg/h removed. Δh requires the same dry-air basis; a point difference alone is not equipment power.

DEHUMIDIFICATION

The route depends on how water leaves the air.

ProcessDirection on this chartCheck before selection
Cooling and condensationLeft at nearly constant w until condensation; then left and down as water condenses. Reheat moves right at constant w.Coil temperature, bypass, defrost and actual removal at inlet conditions.
Desiccant adsorptionTypically down and right: moisture falls while adsorption and carry-over heat warm the process air. A constant-enthalpy direction is only an approximation.Regeneration heat, wet-air exhaust and post-cooling requirements.

Common reading mistakes

Lower RH does not necessarily mean less water: reheating can lower RH at constant w. Wet-bulb and enthalpy lines are close, but not identical. Pressure changes the chart. Never read a sea-level chart as an altitude-corrected result.

Calculation method and example

pᵥ = RH × pws(T) / 100
w = 0.621945 × pᵥ / (p − pᵥ)
h = 1.006T + w(2501 + 1.86T)
v = 287.042(T + 273.15)(1 + 1.607858w) / p

Pressure is in Pa, T in °C, w in kg/kg dry air, h in kJ/kg dry air and v in m³/kg dry air. At 25°C, 60% RH and 101.325 kPa: w ≈ 11.90 g/kg, h ≈ 55.45 kJ/kg. Dew point is found by inverting saturation pressure; wet bulb solves the thermodynamic water/ice energy balance.

Source: ASHRAE Handbook—Fundamentals (2017), Chapter 1 · PsychroLib. Hyland–Wexler saturation equations use ice up to 0.01°C and liquid water above. The interface deliberately limits dry bulb to −20…60°C. Ideal-gas engineering approximations and rounded chart lines are not a laboratory calibration.

Estimate the room moisture load and required dehumidifier capacity

NEXT / PROJECT REVIEW

Turn the air states into equipment requirements.

Bring inlet and target states, airflow, moisture sources and installation constraints.

Review project requirements